(2x+1)(4x^2-2x+1)=0

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Solution for (2x+1)(4x^2-2x+1)=0 equation:


Simplifying
(2x + 1)(4x2 + -2x + 1) = 0

Reorder the terms:
(1 + 2x)(4x2 + -2x + 1) = 0

Reorder the terms:
(1 + 2x)(1 + -2x + 4x2) = 0

Multiply (1 + 2x) * (1 + -2x + 4x2)
(1(1 + -2x + 4x2) + 2x * (1 + -2x + 4x2)) = 0
((1 * 1 + -2x * 1 + 4x2 * 1) + 2x * (1 + -2x + 4x2)) = 0
((1 + -2x + 4x2) + 2x * (1 + -2x + 4x2)) = 0
(1 + -2x + 4x2 + (1 * 2x + -2x * 2x + 4x2 * 2x)) = 0
(1 + -2x + 4x2 + (2x + -4x2 + 8x3)) = 0

Reorder the terms:
(1 + -2x + 2x + 4x2 + -4x2 + 8x3) = 0

Combine like terms: -2x + 2x = 0
(1 + 0 + 4x2 + -4x2 + 8x3) = 0
(1 + 4x2 + -4x2 + 8x3) = 0

Combine like terms: 4x2 + -4x2 = 0
(1 + 0 + 8x3) = 0
(1 + 8x3) = 0

Solving
1 + 8x3 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 8x3 = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 8x3 = 0 + -1
8x3 = 0 + -1

Combine like terms: 0 + -1 = -1
8x3 = -1

Divide each side by '8'.
x3 = -0.125

Simplifying
x3 = -0.125

Reorder the terms:
0.125 + x3 = -0.125 + 0.125

Combine like terms: -0.125 + 0.125 = 0.000
0.125 + x3 = 0.000

The solution to this equation could not be determined.

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